Originally Posted By: Ken Condon
pH being .05


log(0.05) = log(5*10^{-2}) = log(5) + log(10^{-2}) = log(5) +(-2)*
log(10)
= log(5) -2*1 = log(5) - 2.

Now, log(5) = 0.69897... and so

log(0.05) = 0.69897 - 2

= -1.30103


There's nothing wrong with thinking
Except that it's lonesome work
sevil regit